


IntroductionAmplifiers have a specific power, which is indicated in Watts. The power is the product of current and voltage. In a loudspeaker the supplied electrical power is converted almost exclusively in heat. Only a fraction of the electrical power can be converted from loudspeakers into sound energy. This relationship describes the efficiency, which is indicated in per cent. Without proving it, e.g. a sound power of 30 Watts would cause an indescribable volume. With hifi the amplifier power output is measured by alternating voltages. Measuring with DC voltage everything would be simpler. Measuring with DC voltages is not possible. Most audio amplifier does not transfer DC voltages. The background for it is that a woofer coil can be easily destroyed by DC voltage, therefore is in such a way designed the amplifiers that DC voltage is not amplified. Meaning of the output power for an audio amplifierHow much output power needed, in addition a few questions:
Can you answer these questions clearly? Probably you do not know actually needed power output. I also not. It is perfectly indifferently how much power output an hifi amplifier has. The amp must supply only the desired volume in the desired quality with your loudspeakers. It is technically possible to build an amplifier with only 30 Watts that is better than a 200 Watt amplifier with same low volume level. With high loads, which demand more than rated output, to which "small one" naturally throws up the sponge, might be logical. The question of which amplifiers the better one is, that with 30 Watts or with 200 Watts, it is not a question of the power, but alone a question of the construction, specification and the electrical special equipment (e.g. protective circuits for amplifiers and loudspeakers). What would you have rather?A formula 1 engine with 800 HP or a modern marine diesel with 800 HP? I rather take a modern marine diesel. Why? The marine diesel has a torque plot, of it dreams the formula 1 engine at night. The marine diesel has a long service life and a full power firmness, of it dreams the formula 1 engine during whole race. In the comparison, many amplifiers must be built after economical considerations. The placement robot in the assembly hangar, it must be constant in motion. In mass production the number of elements per equipment is to be small. Expensive elements are not applicable in many cases from cost reasons. The average customer's request required for payable achievement, understandably orients itself mass production to it. A good amplifier with high power and low manufacturing costs to build is a tightrope act. In addition the elements must be often loaded to to their absolute maximum ratings. The manufacturer calculates by right into his development also that the user demands the maximum power only most rarely. In other words: many of the constructions are not appropriate for continuous stress under full load. Some cooling systems are not appropriate for the rated output. The transistors and thus the heat sinks, become very hot (try it). That heats the interior and other construction units e.g. electrolyte condensers, which lose on life span. How much per cent of the maximum power takes a music signal up at all, is entitled other question, whose answer extends the life of most amplifiers clearly End of the discussion: the answer is that most amplifiers for a realistic medium volume music pleasure are sufficiently cooled, in the long term however only few are appropriate for the indicated rated output. The full powerfirm well cooled 30 Watt amplifier achieves a similar size and still higher costs than the 200 Watts paper tiger. The smaller need according to power made it possible to built better circuits. However only few customers would buy the small expensive exclusively developed amplifier. Therefore a majority of the industrie does not build this amplifier at all, only for enthusiasts. I want to never say thereby the industry build bad amplifiers, the industry build very good amplifiers in a very good pricepower relationship. Somebody who is cocksure, nothing more leaves itself to improve, has only little knowledge. 
Mathematics and Power 

simulated period, 2 ohms load resistance
2 kHz signal frequency of 5 volts current according to Ohm's law power (t) = voltage (t) * current (t) 
Figure 1 shows the course of the power in black. As signal a sinusoidal voltage was applied. With Ohm's load the current is also sinusoidal. The power is multiplied the product of current and voltage in the time intervall with one another. The power is here always positive, it becomes never smaller zero. In practice means this, the load returns the delivery at no time energy to the amplifier. In zero by the voltage is also the power zero, in the maximum of the voltage reachs also the power its maximum. 
In this case reaches the power at 125 milliseconds the maximum of 12,5 Watt. 
The mean power, the root mean square voltage and the root mean square current can be computed. T is the period duration. The RMS current from the temporally square average value, produces the same heat in an resistor as a equivalent large direct current. The effective power can be computed for Ohm's loads also in such a way: 

These are valid the equations for the computation of the power of an amplifier, for Ohm's loads. 

Der Widerstand "R" wird mit einer Leistung von 6,25 Watt beheizt. Dies entspricht genau dem linearen Mittelwert "meanpower" des zeitlichen Verlaufs der Leistung "power(t)". Von "power(t)" nochmal den Effektivwert zu bilden wäre falsch, da für Leistungen keine Effektivewerte existieren, sondern nur Mittelwerte. Die Berechnung eines Effektivwertes ergibt nur einen Sinn für Ströme und Spannungen, nicht für Leistungen. Die oft benutzte Bezeichnung "RMSpower" entspricht genau genommen dem zeitlich linearen Mittelwert der Leistung "meanpower" The "R" is heated with an output of 6,25 Watts. This corresponds exactly to the linear mean value "meanpower" the course of "power(t)". To form the rms of "power(t)" again, would be wrong, since for power exists no effective values, but only for mean values . It's only wise to compute an rms for currents and voltages, not for power. The often used designation "RMSpower" corresponds exactly taken to the temporally linear mean value of the "meanpower". 

The equation on the left side results in physically no sense. RMS can be formed only for currents or voltages, not for power. 


How the amplifiers power can be measured?
Suitable measuring instruments and frequent measuring methods:
